Question

Asked Sep 11, 2019

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Step 1

Given:

T_{1} = 300°C

X_{1 }= 0.5

X_{2} = 1.0

T_{0} = 300 K

P_{0 }= 1 bar

Assumptions:

- The water is a closed system.
- The volume is constant.
- In case (a); Q =0 and in case (b); W=0.
- Kinetics and potential effects are negligible.

For both the cases the initial and final states are same. Let us begin by obtaining data at each state. From the thermodynamic table at temperature 300°C.

Step 2

From the assumptions (1) and (2); v_{2} = v_{1}= v_{g}(T_{2})

From the thermodynamic table

T_{2} = 336.8°C

U_{2} = 2474.2 KJ/Kg

S_{2} = 5.3673 KJ/Kg

Step 3

For part (a): In this case, the volume is constant. ...

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