f(t) dt where f(t)= Consider the function B defined by the rule B(r) 11 6-2t. 1. Compute B(1) and B(2) exactly 2. Use the first Fundamental Theorem of Calculus to find a formula for B(r) that does not involve integrals. That is, use the first FTC to evaluate (G-21) dt. 3. Ohserve that f is a linear function: what kind of function is B? 4. Using the formula that you found in part (b) that does not involve inte- grals. compute B' (r). 5. While we have defined f by the rule f(t) 6- 2f., it is equivalant to say that fis given by the rule f(r) = 6-2.r. What do you observe about the relationship between B and f?

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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f(t) dt where f(t)=
Consider the function B defined by the rule B(r)
11
6-2t.
1. Compute B(1) and B(2) exactly
2. Use the first Fundamental Theorem of Calculus to find a formula for B(r)
that does not involve integrals. That is, use the first FTC to evaluate
(G-21) dt.
3. Ohserve that f is a linear function: what kind of function is B?
4. Using the formula that you found in part (b) that does not involve inte-
grals. compute B' (r).
5. While we have defined f by the rule f(t) 6- 2f., it is equivalant to say
that fis given by the rule f(r) = 6-2.r. What do you observe about the
relationship between B and f?
Transcribed Image Text:f(t) dt where f(t)= Consider the function B defined by the rule B(r) 11 6-2t. 1. Compute B(1) and B(2) exactly 2. Use the first Fundamental Theorem of Calculus to find a formula for B(r) that does not involve integrals. That is, use the first FTC to evaluate (G-21) dt. 3. Ohserve that f is a linear function: what kind of function is B? 4. Using the formula that you found in part (b) that does not involve inte- grals. compute B' (r). 5. While we have defined f by the rule f(t) 6- 2f., it is equivalant to say that fis given by the rule f(r) = 6-2.r. What do you observe about the relationship between B and f?
Expert Solution
Step 1

Given f(x)=6-2t, the fuction B(x) is defined by

B(x)=f(t)dt
Step 2

B(1) and B(2) can be evaluated as

1
B(1)- f)di-j(6-2t)dt - [6r--0
__
=
2
2
B(2)-5)d[(6-21) d - [r-f[6(2)-(2)]6)-(]3
=6t
=
1
Step 3

If F'(t)=f(t),then by Fundamental theorem of calculus, we have

t)=F(b)-F(a)
a
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