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f(x) = 14 csc(3x/2) , (0, 2π)Describe the concavity. (Enter your answers using interval notation. If an answer does not exist, enter DNE.)

Question

f(x) = 14 csc(3x/2) , (0, 2π)


Describe the concavity. (Enter your answers using interval notation. If an answer does not exist, enter DNE.) 

check_circleAnswer
Step 1

The given funct...

Зх
(0,27)
f(x)14csc
2
Differentiate f (x) with respect to x as follows
3х
14 csc
2
f(x)
dx
3x
3х
-14
2
cot
CSC
2
2
3x
cot
2
3х
-21csc
2
Again differentiate f'(x)
with respect tox as follows.
Зx
-21 csc
cot
2
3x
f"(x)
dx
2
3x
3х
cot2
2
3х
csc2
2
63
-CSC
2
_
2
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Image Transcriptionclose

Зх (0,27) f(x)14csc 2 Differentiate f (x) with respect to x as follows 3х 14 csc 2 f(x) dx 3x 3х -14 2 cot CSC 2 2 3x cot 2 3х -21csc 2 Again differentiate f'(x) with respect tox as follows. Зx -21 csc cot 2 3x f"(x) dx 2 3x 3х cot2 2 3х csc2 2 63 -CSC 2 _ 2

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