f(z) = 16 – z/3 Find f(– 64) and f(64). f(– 64) = %3D f(64) Find all values cin (-64, 64) such that f'(c) = 0. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) C = Based off of this information, what conclusions can be made about Rolle's Theorem? O This does not contradict Rolle's Theorem, sincef (0) = 0, and 0 is in the interval (- 64, 64) O This does not contradict Rolle's Theorem, since f (0) does not exist, and so f is not differentiable on (- 64, 64). O This contradicts Rolle's Theorem, since f is differentiable, f(-64) = f(64), and f'(c) 0 exists, but c is not in (-64, 64). O Nothing can be concluded. O This contradicts Rolle's Theorem, since f(- 64) f(64) there should exist a number cin (- 64, 64) such that f'(c) 0.

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter8: Polynomials
Section8.5: Solution Of Cubic And Quartic Equations By Formulas (optional)
Problem 32E
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f(x) = 16 – 2/3
Find f(- 64) and f(64).
f(– 64)
f(64) =
Find all values cin (-64, 64) such that f (c) 0 (Enteryour answers as a comma-separated
list. If an answer does not exist, enter DNE.)
Based off of this information, what condlusions can be made about Rolle's Theorem ?
OThis does not contradict Rolle's Theorem, since f (0) 0, and 0 is in the interval (-64, 64)
O This does not contradict Rolles Theorem, since f (0) does not exist, and so fis not
differentiable on (-64, 64).
O This contradicts Rolle's Theorem, since f is differentiable, f(- 64) f(64), and f'(c) 0
exists, but cis not in (-64, 64).
O Nothing can be concluded.
O This contradicts Rolle's Theorem, since f(-64) f(64) there should exist a nurmber cin
(- 64, 64) such that f'(c) 0.
Transcribed Image Text:f(x) = 16 – 2/3 Find f(- 64) and f(64). f(– 64) f(64) = Find all values cin (-64, 64) such that f (c) 0 (Enteryour answers as a comma-separated list. If an answer does not exist, enter DNE.) Based off of this information, what condlusions can be made about Rolle's Theorem ? OThis does not contradict Rolle's Theorem, since f (0) 0, and 0 is in the interval (-64, 64) O This does not contradict Rolles Theorem, since f (0) does not exist, and so fis not differentiable on (-64, 64). O This contradicts Rolle's Theorem, since f is differentiable, f(- 64) f(64), and f'(c) 0 exists, but cis not in (-64, 64). O Nothing can be concluded. O This contradicts Rolle's Theorem, since f(-64) f(64) there should exist a nurmber cin (- 64, 64) such that f'(c) 0.
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