g array: x = [1,2,3,4,5;6,7,8,9,10;11,12,13,14,15;16,17,18,19,20] What Octave command returns the number of elements of array x along the largest dimension

Write code to identify an element in a sorted array of n numbers that has been rotated an unknown number of times. You may presume the array was initially sorted in ascending order.EXAMPLElnput:15, 16, 19, 20, 25, 1, 3, 4, 5, 7, 10, 148 as an output (the index of 5 in the array)

May you please explain each line I starred and why they have these output values. Thank you!

We have an array variable ‘var’ int var[4] = {25,20,30,40}; Find the memory address of the first element of in the array: var[0]

Below is how the arrays are represented ARRAY1[] = [1, 5, 6, 6, 9, 9, 9, 11, 11, 21] Here length of ARRAY1 is m. ARRAY2[] = [6, 6, 9, 11, 21, 21, 21] Here length of ARRAY2 is n. Array to be returned would be: ARRAY[] = [6, 9, 11, 21] ATTN : Further, please be reminded that you cannot use library functions to either sort and or perform the de-duplication operation. solve the problem in two ways In a separate implementation, code up a solution in such a way that your solution solves the problem with O(nlog(m)) time complexity 2 or O(mlog(n)) time complexity. Here log means to the base of 2. I’m sure you already know that the hint is to use Binary Search. In the form of sentences, as a comment in your code (at the bottom of your Solution2), you are required to suggest how can Solution2 be improved by leveraging the fact that both the arrays are already sorted. Suggest a solution so that your suggested solution can run linearly with O(m + n) time complexity. Your suggestion should be no…