Gaseous butane (CH,(CH,) CH, will react withgaseous oxygen (0,) to produce gaseous carbon dioxide (CO,) and gaseous water (H,0). Suppose 3.5 gof butane is mixed with 17.1 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer3.2.to 2 significant digits.x10oloArExplanationCheck2019 McGraw-Hill Education. All Rights Reserved/PrivacyTeerma of Use925 PM12/5/2019O Type here to search99+hpB8pginsprt scpg upt12endf10homedeletefgf8f7f6f510esc&numbackspacelock8.6.{8.home6,96%24%23

Question
Asked Dec 6, 2019
66 views
Gaseous butane (CH,(CH,) CH, will react with
gaseous oxygen (0,) to produce gaseous carbon dioxide (CO,) and gaseous water (H,0). Suppose 3.5 g
of butane is mixed with 17.1 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer
3.
2.
to 2 significant digits.
x10
olo
Ar
Explanation
Check
2019 McGraw-Hill Education. All Rights Reserved
/
Privacy
Teerma of Use
925 PM
12/5/2019
O Type here to search
99+
hp
B8
pg
ins
prt sc
pg up
t12
end
f10
home
delete
fg
f8
f7
f6
f5
10
esc
&
num
backspace
lock
8.
6.
{
8.
home
6,
96
%24
%23
help_outline

Image Transcriptionclose

Gaseous butane (CH,(CH,) CH, will react with gaseous oxygen (0,) to produce gaseous carbon dioxide (CO,) and gaseous water (H,0). Suppose 3.5 g of butane is mixed with 17.1 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer 3. 2. to 2 significant digits. x10 olo Ar Explanation Check 2019 McGraw-Hill Education. All Rights Reserved / Privacy Teerma of Use 925 PM 12/5/2019 O Type here to search 99+ hp B8 pg ins prt sc pg up t12 end f10 home delete fg f8 f7 f6 f5 10 esc & num backspace lock 8. 6. { 8. home 6, 96 %24 %23

fullscreen
check_circle

Expert Answer

Step 1

The chemical balanced reaction is written as follows:

help_outline

Image Transcriptionclose

2C H, + 130, — 8со, +10н,О — 8со, + 10н,О

fullscreen
Step 2

The calculation of moles of butane and oxygen as follows:

help_outline

Image Transcriptionclose

mass of butane moles of butane=- molar mass of butane 5.5g 58.12 g / mol = 0.09463 mol mass of oxygen moles of oxygen=- molar mass of oxygen 17.1 g 32g / mol =0.5343 mol determining the limiting reactant : 2 mole of C,H reacts with 13 mol of 0, 13 mol O, 0.09463 mol of C_H, ×0.09463 mol of C _H. 2 mol C̟H, = 0.615 mol O,

fullscreen
Step 3

As oxygen molecules are less than the required, it is the limiting reactant.  Th...

help_outline

Image Transcriptionclose

13 mol O, forms 8 mol of CO, 8 mol CO, moles of CO, produced=0.5343 mol O, x- 13 mol O, = 0.3288 mol CO, mass of CO, produced=moles of CO, ×molar mass of CO, = 0.3288 mol× 44.01 g / mol =14.47 g

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Chemistry

Related Chemistry Q&A

Find answers to questions asked by student like you
Show more Q&A
add