We suspect that Method 1 for detecting impurities in iron ingots yields higherresults than Method 2 for finding such impurities. We want to give a 90%confidence interval for the difference in the average number of impuritiesdetected by the two methods. In order to obtain the confidence interval, wemeasured the impurities of 3 ingots, employing both methods for each ingot. Theresults are presented in the table below.We let l1 denote the population average number of defects for Method 1 and H2denotes the population average number of defects for Method 2. We wish todevelop a confidence interval for µd = H1 – H2Give the margin of error for the 90% confidence interval for ua = µ1 – µ2Ingot 1Ingot 2Ingot 3Method 1163212Method 2122610

The differences are 4, 6, 2. The mean is, d¯=∑dn=4+6+23=123=4 The standard deviation is,…

Answered: Give the margin of error for the 90%…

Math

Statistics

Give the margin of error for the 90% confidence interval for µd = µ1 – H2

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A research article reported that for a sample of 50 kitchens with gas cooking appliances monitored…

Q: A random sample of 100 teachers in a large metropolitan area revealed a mean weekly salary of $487…

A: Obtain the 95% confidence interval for the population mean weekly salary. The 95% confidence…

Q: Find the critical values, χ L 2 and χ R 2, used for a 95% confidence interval for the standard…

A: Given: Degree of freedom = 25 α = 1 - 0.95 = 0.05

Q: Find the critical values x²1-α/2 and x² X²1-α/2= (Round to three decimal places as needed.) for a…

A: Chi square is the test which used to determine the relationship between the categorical variable. It…

Q: The resistance in milliohms of 1 meter of copper cable at a certain temperature is normally…

A: Given: μ=23.8 and σ2=1.28. a)The value of z at 95% confidence level is 1.96. Then, the 95%…

Q: For an upper-tail test at the 1% significance level, what is the appropriate critical value when a…

A: When the sample of small size is drawn from a normal population with unknown SD, the we use critical…

Q: Find the critical value corresponding to a 95% confidence interval for a population mean with an…

A: The confidence level is 0.95.

Q: A random sample of 50 helmets (to protect motorcyclists) was subjected to a crash test and 15…

A: Given : Sample Size, n = 50 Number of successes, x = 15 confidence level,c=0.95

Q: An electrical engineer wishes to compare the mean lifetimes of two types of transistors in an…

A: To determine: Find a 95% confidence interval for the difference between the mean lifetimes of the…

Q: A random sample of size 15 taken from a normally distributed population revealed a sample mean of 75…

A: E. Given information: sample mean=75 sample variance=25 Sample standard deviation=5 sample size=15…

Q: In a sample of 40 water specimens taken from a construction site 26 contained detectable level of…

A: According to the provided information, sample size (N)=40 number of favorable cases (X) = 26 The…

Q: A 30 month study is conducted to determine the difference in rates of accidents per month between…

A: Given:x1=12.3s1=3.5n1=12 and x2=7.6s2=3.4n2=9 Since, the…

Q: A sample of size n = 10 is drawn from an approximately normal population whose standard deviation is…

A: Givensample Mean(x)=50.9standard deviation(σ)=12.5sample size(n)=10Confidence interval = 99%

Q: Suppose that the population standard deviation of student scores is 20. What will be the sample size…

Q: Find the critical value X2R and X2L corresponding to a sample size of 11 and a confidence level of…

Q: Find the critical value zα/2 that corresponds to a 91% confidence level.

A: We have given that, Confidence interval = 91% Then, significance level (alpha) = 0.09 If x are…

Q: A 30 month study is conducted to determine the difference in rates of accidents per month between…

Q: A random sample of 100 observations produced a mean x̅ =38.5 and a standard deviation of 3.2. find a…

A: Given information Sample size(n) = 100 Sample mean x̅ =38.5 Sample standard deviation = 3.2…

Q: State the statistical hypotheses against a population with a mean of 90 for a one-tailed test where…

A: Given: μ=90 The hypotheses for testing the population mean is given bellow: Null hypothesis: H0:…

Q: Let the mean of the chance sample with a width of n = 9 taken in a normally distributed population…

A: The confidence interval gives a plausible range of values for an unknown parameter based on the…

Q: From a population with a variance of 484, a sample of 256 items is selected. At 95% confidence, what…

Q: A random sample of 40 adults with no children under the age of 18 years results in a mean daily…

A: There are two independent samples which are adults with no children under the age of 18 and adults…

Q: During a natural gas shortage, a gas company randomly sampled residential gas meters in order to…

A: Solution: Let X be the gas consumption. From the given information, x-bar=250 cubic feet, S=50 cubic…

Q: A group of 10 surgery patients had a mean weight of 240 pounds with a sample standard deviation of…

Q: During a routine check of the fluoride content of Gotham City's water supply, the given results were…

Q: Of 1000 randomly selected cases of lung cancer, 823 resulted in death. H0: p=0.85 Ha: p does not…

A: Confidence interval: The (1-α) % confidence interval for proportion p is given by,

Q: Find a 95% confidence interval for the variance when a random sample of size 10 is taken from a…

A: From the given information, the sample size is 10 and the sample variance is 16.00. Given that the…

Q: Determine the point estimate of the population mean and margin of error for the confidence interval…

A: Point estimate: The population parameter which is estimated by using sample statistic is termed as…

Q: A) Test H0 : σ 2 X = σ 2 Y versus H1 : σ 2 X 6= σ 2 Y with significance level α = 0.05 B) Assume σ…

A: The variance between the two samples are tested using the F test. The test statistic of f test is…

Q: An epidemiologist needs to estimate the proportion of residents of St. Lucie county that have been…

Q: A random sample of size 15 taken from a normally distributed population revealed a sample mean of 75…

A: The given values are sample size = n= 15 Sample mean = X = 75 Sample variance = S 2=25

Q: Find the error margin for a 98% confidence interval for the average value of Y when X is 9.

A: Given: The error margin for 98% confidence internal for the average value of Y when X is 9

Q: The average earnings per share (EPS) for 10 industrial stocks randomly selected from those listed on…

A: Given data,n=10x=1.85s=0.395α=0.01df=n-1=9t-critical value is tc=3.250

Q: Find the desired sample size for a 90% confidence interval with a margin of error equal to 0.03

A: Given information: Denote the population proportion as p. Since, the preliminary estimate of the…

Q: A random sample of 50 roundtrip flights between New York and Chicago has an average airfare of $400…

A: Given : A random sample of 50 round-trip flights between New York and Chicago has an average airfare…

Q: in a study of 150 randomly selevted accidents that required treatment in and ER 36% involed children…

Q: A sample of 60 obese adults was put on a low carbohydrate diet for a year. The average weight loss…

A: Given: Mean = 11 Standard deviation = 9 The one-tailed critical value for a 99% confidence level is…

Q: If 10 measurements of the density of a certain kind of glass had a variance of 0.0012, construct a…

A: Given: n = 10 s2 = 0.0012 Confidence level = 99% Formula used: Confidence interval = (n-1)s2χα22 ≤…

Q: Find the critical value, t c, used for a 97% confidence interval for the mean with a sample size of…

A: The confidence level is, 100 (1 – α) % = 97%. Hence, (1 – α) = 0.97, and the significance level is,…

Q: An article reported that for a sample of 58 kitchens with gas cooking appliances monitored during a…

Q: 1. The impact rebound values of n=15 pieces of rock, randomly selected from a large geological…

Q: A random sample of 15adultRainbow trout in a fish hatchery showed the average weight was 3.5pounds…

A: In question, given that, a random sample of 15 adult rainbow trout in a fish hatchery having an…

Q: A sample of size 25 drawn from a normally distributed population has a sample mean 12 and a sample…

Q: For a random sample of 36 items and a sample mean of 211, compute a 95% confidence interval for u if…

A: According to the given information, we have Population standard deviation = 23 Sample size = 36…

Q: epidemiologist needs to estimate the proportion of residents of St. Lucie county that have been…

A: The margin of error is 0.026.

Q: To construct a 95% confidence interval of variance using a sample of 18 the critical values used are…

A: In question, We'll find the critical values for construct a 95% confidence interval of variance…

Q: A sample of 120 students yielded a sample mean GPA of 3.35, end a sample standard deviation equal to…

A: Obtain the 95% confidence interval for the population mean GPA. The 95% confidence interval for the…

Q: A sample of size 78 produced the sample mean of 16.4. Assuming the population standard deviation…

A: Givensample size(n)=78sample mean(x)=16.4standard deviation(σ)=3.3α=1-0.99=0.01α2=0.005Critical…

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

We suspect that Method 1 for detecting impurities in iron ingots yields higher
results than Method 2 for finding such impurities. We want to give a 90%
confidence interval for the difference in the average number of impurities
detected by the two methods. In order to obtain the confidence interval, we
measured the impurities of 3 ingots, employing both methods for each ingot. The
results are presented in the table below.
We let l1 denote the population average number of defects for Method 1 and H2
denotes the population average number of defects for Method 2. We wish to
develop a confidence interval for µd = H1 – H2
Give the margin of error for the 90% confidence interval for ua = µ1 – µ2
Ingot 1
Ingot 2
Ingot 3
Method 1
16
32
12
Method 2
12
26
10

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

An epidemiologist with the Florida Department of Health needs to estimate the proportion of Floridians who are infected with the corona virus but are asymptomatic (show no signs of the virus). The epidemiologist compiled a preliminary random sample of infected patients and found that 65% of the sample were also asymptomatic.How large a sample should be selected such that the margin of error of the estimate for a 96% confidence interval is at most 1.93%. Round the solution up to the nearest whole number.
A random sample of size 30 from a normal population yields x̅ = 69 and s = 4. The lower bound of a 95 percent confidence interval is (Round off upto 2 decimal places).
From a large number of actuarial exam scores, a random sample of 200 scores is selected, and it is found that 148 of these 200 are passing scores. Based on this sample, find a 90% confidence interval for the proportion of all scores that are passing. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. What is the lower limit of the 90% confidence interval? What is the upper limit of the 90% confidence interval?
A statistical research yields to the sample proportion of a certain feature in a certain community be 0.43. Find the required sample size for a maximum margin of error of 0.06 for a 90% confidence interval.
A recent survey of 200 households showed that 8 had a single male as the head of the household. Forty years ago, a survey of 200 households showed that 6 had a single male as the head of the household. At alpha=0.05, can it be concluded that the proportion has changed? Find the 95% confidence interval of the difference of the two proportions. Does the confidence interval contain 0? Why is this important to know?
An epidemiologist with the Florida Department of Health needs to estimate the proportion of Floridians who are infected with the corona virus but are asymptomatic (show no signs of the virus). The epidemiologist compiled a preliminary random sample of infected patients and found that 77% of the sample were also asymptomatic . How large a sample should be selected such that the margin of error of the estimate for a 99% confidence interval is at most 4.39 %. Round the solution up to the nearest whole number .
A random sample of size 15 taken from a normally distributed population revealed a sample mean of 75 and a sample variance of 25. The upper limit of a 95% confidence interval for the population mean would equal?
Your stats teacher wants to estimate the proportion of people at New Jersey beaches who are wearing sunscreen with a SPF of 30 or more. If they wanted to devote a whole summer to taking 500 different random samples of 100 people each time and making 500 different 95% confidence intervals, about how many of those confidence intervals would be expected to actually contain the true, unknown population proportion of people at New Jersey beaches who wear factor 30+ sunscreen, and about how many intervals are expected to “miss” the parameter?
A 30 month study is conducted to determine the difference in rates of accidents per month between two departments in an assembly plant. If a sample of 12 from the first department averaged 12.3 accidents per month with a standard deviation of 3.5, and a sample of 9 from the second department averaged 7.6 accidents per month with standard deviation of 3.4, find: The t-value for a 95% confidence interval is:
In order to estimate the average GPA of all students at SCC, we selected a random sample of 36 students and found that their average GPA is 2.1 with a s. d. of 0.8.Construct a 95% confidence interval for the average GPA of all students at SCC.
A soft-drink manufacturer purchases aluminum cans from an outside vendor. A random sample of 70 cans is selected from a large shipment, and each is tested for strength by applying an increasing load to the side of the can until it punctures. Of the 70 cans, 51 meet the specification for puncture resistance. a) Find the sample size needed for a 90% confidence interval to specify the proportion to within ±0.06. Round up the answer to the nearest integer. b) If a 90% confidence interval is computed each day for 300 days, what is the probability that more than 280 of the confidence intervals cover the true proportions? Round the answer to three decimal places.
To assess the accuracy of a laboratory scale, a standard weight that is known to weigh 1 gram is repeatedly weighed a total on n times and the mean of x of the weighing is completed. Suppose the scale readings are j BJ or ally distributed with unknown mean u And the standard deviarion a= 0.01g. How large should n be so that a 95 % confidence interval for u has a margin of error of error of +|- 0.001?