Given 2 conductors in a free space, the electric field produced by a difference in voltage potential between them is calculated by: E 9 4πεd2 Where: E = Electric Field Strength (Volts per meter) q=charge between conductors (Coulombs) ε = permittivity (Farads per meter) d = distance between conductors (meter) At what distance from a negative charge of 5.5360 nC would the electric field strength be 1.90 x 10³ N/C? (Permittivity of free space is approximately = 8.8542 pF/m) f(x) = (Write the function used)

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Given 2 conductors in a free space, the electric field produced by a difference in voltage
potential between them is calculated by:
E =
9
4πɛd²
Where:
E = Electric Field Strength (Volts per meter)
q=charge between conductors (Coulombs)
ε = permittivity (Farads per meter)
d = distance between conductors (meter)
At what distance from a negative charge of 5.5360 nC would the electric field strength be
1.90 x 105 N/C?
(Permittivity of free space is approximately = 8.8542 pF/m)
f(x)
(Write the function used)
Transcribed Image Text:Given 2 conductors in a free space, the electric field produced by a difference in voltage potential between them is calculated by: E = 9 4πɛd² Where: E = Electric Field Strength (Volts per meter) q=charge between conductors (Coulombs) ε = permittivity (Farads per meter) d = distance between conductors (meter) At what distance from a negative charge of 5.5360 nC would the electric field strength be 1.90 x 105 N/C? (Permittivity of free space is approximately = 8.8542 pF/m) f(x) (Write the function used)
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