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Given thatlim x→1 (4x − 3) = 1,illustrate Definition 2 by finding values of δ that correspond to ε = 0.1, ε = 0.05, and ε = 0.01.ε = 0.1    δ≤1ε = 0.05    δ≤2ε = 0.01    δ≤3

Question

Given that

lim x→1 (4x − 3) = 1,

illustrate Definition 2 by finding values of δ that correspond to ε = 0.1, ε = 0.05, and ε = 0.01.

ε = 0.1     δ 1
ε = 0.05     δ 2
ε = 0.01     δ 3
check_circleAnswer
Step 1

To find the value of delta (following the  definition of the limit of a function ) for the given function (and given epsilons)

Step 2

Recall the epsilon -delta definition of the limit of a function at a point a.

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Step 3

The existence of limit is no issue. But we want to find the values of delta corresponding to the values of epsilons given. In our ...

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Math

Calculus

Limits

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