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Asked Aug 20, 2019
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Given the partial decomposition of the rational function f(x), find A, B and C.

 

f(x)=(-x^(2)-12x-26)/((x+2)(x+3)(x+4))=(A)/(x+2)+(B)/(x+3)+(C)/(x+4)

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The constant value in partial decomposition of the ratio...

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-x2-12x-26 B C (x+2)(x+3)(x+4) (x+2) (x+3) x4) A (x+3 x4) B(x2)(x+ 4) (x2) C(x+2)(x3) + + (x+3) (x+4) A(x+3) (x+4)+ B(x2)(x+4)+C (x+2)(x+3) (x+2)(x+3)(x4)

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