Given the thermochemical equations X2 + 3Y2 ⟶ 2XY3   ΔH1 = −380 kJX2 + 2Z2 ⟶ 2XZ2   ΔH2 = −180 kJ 2Y2 + Z2 ⟶ 2Y2Z   ΔH3 = −260 kJCalculate the change in enthalpy for the reaction.4XY3 + 7Z2 ⟶ 6Y2Z + 4XZ2

Chemistry: The Molecular Science
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Chapter4: Energy And Chemical Reactions
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Given the thermochemical equations

X2 + 3Y2 ⟶ 2XY3   ΔH1 = −380 kJ

X2 + 2Z2 ⟶ 2XZ2   ΔH2 = −180 kJ

2Y2 + Z2 ⟶ 2Y2Z   ΔH3 = −260 kJ

Calculate the change in enthalpy for the reaction.
4XY3 + 7Z2 ⟶ 6Y2Z + 4XZ2

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