# Given the two reactionsH2S⇌HS−+H+,   K1 = 9.41×10−8, andHS−⇌S2−+H+,   K2 = 1.49×10−19,what is the equilibrium constant Kfinal for the following reaction?S2−+2H+⇌H2S

Question

Given the two reactions

1. H2SHS+H+,   K1 = 9.41×10−8, and
2. HSS2+H+,   K2 = 1.49×10−19,

what is the equilibrium constant Kfinal for the following reaction?

S2+2H+H2S

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Step 1

Equilibrium constants for the given reactions is obtained.

Step 2

To determine the value of Kfinal, relationship between K1, K2 and Kfinal has to be obtained.

Step 3

Kfinal is the inverse of the product of K1 and K2. Hence, the equilibrium constant Kfinal can be determined by substituting the given values of K1 and K2

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