Question
Asked Nov 21, 2019
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Graph the complex number, find its modulus and put the complex number in polar form with argument θ between 0 and 2π
 
(a) 7−3i
(b) −1−√33i
(c) −√2+i√22
(d) −5 + 5√3i
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Expert Answer

Step 1

First, we will graph the given complex numbers.

(a) 7−3i

(b) −1−√33i

(c) −√2+i√22

(d) −5 + 5√3i

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Imaginary Axis 5+5 sqrt(3) 8- 6 sqrt(2)+sqrt(22) 4 2 -6 0 4 6 Real Axis -2 7-3 -1-sqrt(33) -6

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Step 2

Let us first know the method to convert a complex number to its polar form.

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Let z aib = a ib r(cos 0 i sin0), where r = Then z z and e tan 1 х So, For (a) z 7 - 3i r lz V(7)23)2 2 7.616 And tan 0.405 (in radian). Since, z lies in 4th quadrant. Therefore, Arg(z)= -0 = -0.405 For e to lie between 0 to 27t, 0 (Since tan function is of period t.) So, 7 3i 7.616(cos 2.737 i sin 2.737) -0.405T 2.737.

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Step 3

Similarly,   ...

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For (b) -1- V33i r z = Z 2 (-1)2(V33 5.831 /33 And 0 = tan 1.398 (in radian) Since, z lies in 3rd quadrant. Therefore, Arg(z) = -n + 0 = -1.7436. For to lie between 0 to 27t, e = -1.7436 +7T (Since tan function is of period 7t.) 1.398 So, 1 33i = 5.831(cos 1.398 + i sin 1.398)

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Algebra