Question
Asked Oct 24, 2019
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How to graph feasible region?

Graph the feasible region for the given systerm of inequalities
X+ 2y s 8
2े+y 3 8
0RX
0RA
Use the graphing tool on the right to graph the system of inequalities
Click to
enlarge
graph
Click the graph, choose a tool in the palette and follow the instructions to crea
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Graph the feasible region for the given systerm of inequalities X+ 2y s 8 2े+y 3 8 0RX 0RA Use the graphing tool on the right to graph the system of inequalities Click to enlarge graph Click the graph, choose a tool in the palette and follow the instructions to crea

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Expert Answer

Step 1

The given inequalities are,

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.. (1) x+2y 8 . (2) 2x y 8 (3) (4) y0

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Step 2

Consider the inequality (1).

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Since the given inequality is , the points on the line satisfy the inequality Hence, the solid line is used to join the coordinates of the inequality. Now, replace the inequality symbol with an "equals" sign. The equation becomes, x+2y 8. Draw the line x+2y 8

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Step 3

To obtain the half plane on the graph of the inequality, choose the ...

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Substitute (1, 2) in x+2y8. 1+2(2)28 [True 58 Thus, the solution region of the inequality x 2y8 is the half plane which contain the point (1,2)

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