Graph x – 6y = 6 by finding the intercepts.

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter1: Equations And Graphs
Section1.3: Lines
Problem 92E
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Question
Graph x -
3y = 6 by finding the y- and x-intercepts.
We will let x = 0 to find the y-intercept of the graph. We will then let y = 0 to find
the x-intercept.
Since two points determine a line, the y-intercept and x-intercept are enough
information to graph this linear equation.
y-intercept:x =
x-intercept:y = 0
%3D
х — Зу %3D
6
х — Зу%3D 6
Substitute
Substitute
-Зу
х — 3(
%D
O for x.
O for y.
-3y =
X -
6.
To isolate
X =
y, divide
both sides
y =
The x-intercept is (6, 0).
by -3.
The y-intercept is (0, –2).
Since each intercept of the graph is a solution of the equation, we enter the intercepts in a table of solutions below.
As a check, we find one more point on the line. We select a convenient value for x, say, 3, and find the corresponding value of y.
- 3y = 6
- Зу %3D6
X -
Substitute 3 for x.
-3y =
To isolate the variable term, -3y, subtract 3 from both sides.
y =
To isolate y, divide both sides by -3.
Therefore, (3, –1) is a solution. It is also entered in the table.
We plot the intercepts and the check point, draw a straight line through them, and label the line as
х — Зу 3D 6.
y
4
х — Зу 3D 6
y
(х, у)
x – 3y = 6
-2 (
--2)
e y-intercept
(6, 0)
3
4
6.
(6,
e x-intercept
(3, -1)
3
-1 (,-1)
e check point
(0. -2)
Transcribed Image Text:Graph x - 3y = 6 by finding the y- and x-intercepts. We will let x = 0 to find the y-intercept of the graph. We will then let y = 0 to find the x-intercept. Since two points determine a line, the y-intercept and x-intercept are enough information to graph this linear equation. y-intercept:x = x-intercept:y = 0 %3D х — Зу %3D 6 х — Зу%3D 6 Substitute Substitute -Зу х — 3( %D O for x. O for y. -3y = X - 6. To isolate X = y, divide both sides y = The x-intercept is (6, 0). by -3. The y-intercept is (0, –2). Since each intercept of the graph is a solution of the equation, we enter the intercepts in a table of solutions below. As a check, we find one more point on the line. We select a convenient value for x, say, 3, and find the corresponding value of y. - 3y = 6 - Зу %3D6 X - Substitute 3 for x. -3y = To isolate the variable term, -3y, subtract 3 from both sides. y = To isolate y, divide both sides by -3. Therefore, (3, –1) is a solution. It is also entered in the table. We plot the intercepts and the check point, draw a straight line through them, and label the line as х — Зу 3D 6. y 4 х — Зу 3D 6 y (х, у) x – 3y = 6 -2 ( --2) e y-intercept (6, 0) 3 4 6. (6, e x-intercept (3, -1) 3 -1 (,-1) e check point (0. -2)
4
х — Зу %3D 6
3
y
(х, у)
X – 3y = 6
-2 (,-2) - y-intercept
(6, 0)
3
6
(6, O)
e x-intercept
6 0
(3,-1)
-1
,-1)
e check point
(0,-2)
-4
eck 2
Graph x – 6y = 6 by finding the intercepts.
%3D
10
Graph Layers
Clear ll
8
After you add an object to the graph you
7
Delete
can use Graph Layers to view and edit its
6
properties.
5
4
Fill
3
2
1
-10 -9
-8
-7
-6
-4
-3
-2
-1
2
3
4
6.
8.
10
-1
-2
No
-3
Solution
-4
-5
-6
-7
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-9
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e Help
WebAssign. Graphing Tool
Transcribed Image Text:4 х — Зу %3D 6 3 y (х, у) X – 3y = 6 -2 (,-2) - y-intercept (6, 0) 3 6 (6, O) e x-intercept 6 0 (3,-1) -1 ,-1) e check point (0,-2) -4 eck 2 Graph x – 6y = 6 by finding the intercepts. %3D 10 Graph Layers Clear ll 8 After you add an object to the graph you 7 Delete can use Graph Layers to view and edit its 6 properties. 5 4 Fill 3 2 1 -10 -9 -8 -7 -6 -4 -3 -2 -1 2 3 4 6. 8. 10 -1 -2 No -3 Solution -4 -5 -6 -7 -8 -9 -10 e Help WebAssign. Graphing Tool
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