H3CA is a vitally important intermediate in the metabolism of carbohydrates. The compound is widely distributed in plant and animal tissues and fluids. H3CA is a triprotic acid, i.e., it requires three moles of NaOH to fully neutralize one mole of H3CA. a) If it requires 21.35 mL of 0.678 M NaOH(aq) to fully neutralize 0.927 g of H3CA, what is the molar mass of H3CA? Show your work below (and on the back, if needed).b) Given the following % composition, determine the true formula of H3CA: 37.51% C; 4.20% H; 58.29% O.

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Asked Jan 30, 2019
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H3CA is a vitally important intermediate in the metabolism of carbohydrates. The compound is widely distributed in plant and animal tissues and fluids. H3CA is a triprotic acid, i.e., it requires three moles of NaOH to fully neutralize one mole of H3CA. a) If it requires 21.35 mL of 0.678 M NaOH(aq) to fully neutralize 0.927 g of H3CA, what is the molar mass of H3CA? Show your work below (and on the back, if needed).b) Given the following % composition, determine the true formula of H3CA: 37.51% C; 4.20% H; 58.29% O.

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Expert Answer

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Step 1

Part (a):

It is given that 21.35 mL of 0.678 M NaOH(aq) requires to fully neutralize 0.927 g of H3CA

And

We know that

Molarity=(Moles*1000)/Volume(ml)

Hence number of moles of NaOH requires to fully neutralize 0.927 g of H3CA is:

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Step 2

It is also given that H3CA is a triprotic acid, i.e., it requires three moles of NaOH to fully neutralize one mole of H3CA.

Hence

3 mol of NaOH requires to fully neutralize the 1 mol of H3CA

0.0145 mol of NaOH requires to fully neutralize:

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Step 3

Hence molar mass of 0.927 g of H3...

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