he following results are for two independent samples taken from the two populations. Sample 1 Sample 2 n1 = 40 n2 = 50 x-bar1 = 25.5 x-bar2 = 22.8 σ1 = 5.2 σ2 = 6.0 What is the value of the test statistic?

A sample​ mean, sample​ size, and sample standard deviation are provided below. Use the​ one-mean t-test to perform the required hypothesis test at the 10​% significance level.   x=25​, s=10​, n=24​, H0​: μ=24​, Ha​: μ>24   The​ P-value is=? less than 0.01. between 0.01 and 0.05. between 0.05 and 0.1. greater than 0.1.

The manufacturer of the X-15 steel-belted radial truck tire claims that the mean mileage the tire can be driven before the tread wears out is 60,000 miles. The population standard deviation of the mileage is 5000 miles. Crosset Truck Company bought 48 tires and found from this purchase of tires that the average mileage for its trucks is in fact 58,500 miles. Using critical value and p-value approach, undertake a two-tailed test at a significance level of 1%, what is the conclusion?

We have provided a sample mean, sample size, and population standard deviation. In each case, use the one-mean z-test to perform the required hypothesis test at the 5% significance level. x = 20, n = 24, σ = 4, H0: μ = 22, Ha: μ ≠ 22

Using the results obtained for a study on website development below, how would we interpret the results of this hypothesis test?  The claim is the percent of customers who abandon a web page due to long load times is different from 34%. The significance level is 0.10. The test statistic is 2.50.  Select the correct answer below: Reject H0. There is strong evidence to conclude that the percent of customers who abandon a web page due to long load times is greater than 34%. Reject H0. There is NOT strong evidence to conclude that the percentage of customers who abandon a web page due to long load times is greater than 34%. Fail to reject H0. There is strong evidence to conclude that the percent of customers who abandon a web page due to long load times is greater than 34%. Fail to reject H0. There is NOT strong evidence to conclude that the percentage of customers who abandon a web page due to long load times is greater than 34%.

If the p-value of a hypothesis test is equal to 0.035, then the null hypothesis will be rejected for which cases? SELECT ALL THAT APPLY.   a. for a significance level of 0.01   b. for a significance level of 0.10   c. for a significance level of 0.05   d. for a significance level of 0.02

following hypothesis test for matched data: Но : ld H1 : Hd + 0 For a sample of 18, it was found that d = 2.9 and sa = 3.56. Determine each of the following: The value of the test statistic: For a = 0.025, the final conclusion is O A. There is enough evidence to say that Hd = 0 B. There is enough evidence to say that ud # 0 C. There is not enough evidence to say that ld = 0 D. There is not enough evidence to say that Hd + 0.

(2) Choose the one alternative that best completes the statement or answers the question. Assume two independent random samples are available which provide sample proportions. For the first sample assume n₁ = 100 and x₁= 39. For the second sample, assume n₂= 100 and x₂= 49. Test the null hypothesis that the population proportions are equal versus the alternative hypothesis that the proportions are not equal at the 90% confidence level. Frame the test statistic by subtracting the proportion for population 1 from that for population 2. Pick an appropriate z value, p-value and conclusion. Round your answer to the nearest thousandth. Note that this is a two- tailed test. z-value = -1.425 p-value= 0.077 statistically significant z-value = 1.425 p-value= 0.077 statistically significant z-value = -1.425 p-value= 0.077 not statistically significant z-value = 1.425 p-value= 0.154 statistically not significant

A sample of 100 yielded a test statistic of 2.1. For a level of significance of 0.05, the null hypothesis was rejected. What was the sample proportion for the sample of .1 100? What was the p-value for this test? 0.864

with work