he graph of a function f is shown. yA -1 1 oes f satisfy the hypotheses of the Mean Value Theorem on the interval [0, 5]? O Yes, because f has a maximum on the closed interval [0, 5]. O Yes, because f is continuous on the open interval (0, 5) and differentiable on the closed interval [0, 5].

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
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The graph of a function f is shown.
yA
1
Does f satisfy the hypotheses of the Mean Value Theorem on the interval [0, 5]?
Yes, because f has a maximum on the closed interval [0, 5].
Yes, because f is continuous on the open interval (0, 5) and differentiable on the closed interval [0, 5].
Yes, because f is continuous on the closed interval [0, 5] and differentiable on the open interval (0, 5).
No, because f is not differentiable on the open interval (0, 5).
No, because f is not continuous on the open interval (0, 5).
No, because f does not have a minimum on the closed interval [O, 5].
If so, find a value c that satisfies the conclusion of the Mean Value Theorem on that interval. (If an answer does not exist, enter DNE.)
с 3
Transcribed Image Text:The graph of a function f is shown. yA 1 Does f satisfy the hypotheses of the Mean Value Theorem on the interval [0, 5]? Yes, because f has a maximum on the closed interval [0, 5]. Yes, because f is continuous on the open interval (0, 5) and differentiable on the closed interval [0, 5]. Yes, because f is continuous on the closed interval [0, 5] and differentiable on the open interval (0, 5). No, because f is not differentiable on the open interval (0, 5). No, because f is not continuous on the open interval (0, 5). No, because f does not have a minimum on the closed interval [O, 5]. If so, find a value c that satisfies the conclusion of the Mean Value Theorem on that interval. (If an answer does not exist, enter DNE.) с 3
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