Question
Asked Feb 10, 2020
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#44

he
n-
5.0 units of force
g?
120°
Knot
e
3.0 units of force
FIGURE P3.43
?
44. || Four forces are exerted on the object shown in FIGURE P3.44.
(Forces are measured in newtons, abbreviated N.) The net force on
the object is Fnet = F¡ + F, + F,+ F, = 4.0î N. What are (a) F,
and (b) F,? Give your answers in component form.
%3D
6.0 N F,
20°
X-
F4
5.0 N
Idon FIGURE P3.44
P3.45 shows four electric charges located at the corners
nel each other while
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he n- 5.0 units of force g? 120° Knot e 3.0 units of force FIGURE P3.43 ? 44. || Four forces are exerted on the object shown in FIGURE P3.44. (Forces are measured in newtons, abbreviated N.) The net force on the object is Fnet = F¡ + F, + F,+ F, = 4.0î N. What are (a) F, and (b) F,? Give your answers in component form. %3D 6.0 N F, 20° X- F4 5.0 N Idon FIGURE P3.44 P3.45 shows four electric charges located at the corners nel each other while

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Expert Answer

Step 1

Given information:

The resultant of all the forces (Fr) = 4i N

The magnitude of the force (F1) = -5j N (-ve y direction)

The magnitude of the force (F2) = 6 N at direction which makes 200 with +ve x-axis.

                                                    = 6.Cos(200) i + 6.Sin(200) j

                                                     = 5.63 N i + 2.05 N j

Step 2

From the diagram we can say that the vertical forces are balancing each other hence we can write:

F3 + F2sin(20) + F1 = 0

F3 = 5 N - 2.05 N = 2.95 N j

Step 3

Since the resultant is in “+ve” x-direction we can write the force balance equation as follows:

F2...

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