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Hello,(a) In what direction would the ship in Exercise 3.57 have to travel in order to have a velocity straight north relative to the Earth, assuming its speed relative to the water remains 7.00 m/s(b) What would its speed be relative to the Earth?fully is what you're asking for. Exeecise 3.57 is provided below:A ship sets sail from Rotterdam, The Netherlands, heading due north at 7.00 m/s relative to the water. The local ocean current is 1.50 m/s in a direction 40.0º north of east. What is the velocity of the ship relative to the Earth?

Question

Hello,

(a) In what direction would the ship in Exercise 3.57 have to travel in order to have a velocity straight north relative to the Earth, assuming its speed relative to the water remains
7.00 m/s

(b) What would its speed be relative to the Earth?fully is what you're asking for.

 

Exeecise 3.57 is provided below:

A ship sets sail from Rotterdam, The Netherlands, heading due north at 7.00 m/s relative to the water. The local ocean current is 1.50 m/s in a direction
40.0º north of east. What is the velocity of the ship relative to the Earth?

 

check_circleAnswer
Step 1

First resolve the velocity in x and y direction

В
cos
sin
sin 40
400
2 cos40
help_outline

Image Transcriptionclose

В cos sin sin 40 400 2 cos40

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Step 2

Part (a): Direction of ship:

Since the horizontal component of the velocity of boat relative to ground is zero.

0
-v, sin v cos 40 0
sin cos 40
1.5
sin w
cos 40
7
sin 0.164
=sin (0.164)
9.45
help_outline

Image Transcriptionclose

0 -v, sin v cos 40 0 sin cos 40 1.5 sin w cos 40 7 sin 0.164 =sin (0.164) 9.45

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Step 3

Part (b): Ship’s relative speed:

The velocity is only in ver...

y= cos v_ sin 40°
7x cos 9.45 1.5x sin 40
7x 0.986 1.5x 0.642
=7.865
= 7.87 m/s
help_outline

Image Transcriptionclose

y= cos v_ sin 40° 7x cos 9.45 1.5x sin 40 7x 0.986 1.5x 0.642 =7.865 = 7.87 m/s

fullscreen

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