Hello! I am looking for soltions to a question which has already been posted on your site I believe. Its from the text book Physics for Scientists and Engineers, Chapter 5 Laws of motion: A block of mass 2.20 kg is accelerated across a rough surface by a rope passing over a pulley, as shown in figure P5.52. The tension in the rope is 10.0 N, and the pulley is 10.0 cm above the top of the block. The coefficient of kinetic friction is 0.400. A) Determine the acceleration of the block when x= 0.400 m. B) Find the value of x at which the acceleration becomes zero. Thank you!!! ;o)
Hello! I am looking for soltions to a question which has already been posted on your site I believe. Its from the text book Physics for Scientists and Engineers, Chapter 5 Laws of motion: A block of mass 2.20 kg is accelerated across a rough surface by a rope passing over a pulley, as shown in figure P5.52. The tension in the rope is 10.0 N, and the pulley is 10.0 cm above the top of the block. The coefficient of kinetic friction is 0.400. A) Determine the acceleration of the block when x= 0.400 m. B) Find the value of x at which the acceleration becomes zero. Thank you!!! ;o)
College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter4: The Laws Of Motion
Section: Chapter Questions
Problem 85AP: What horizontal force must ho applied to a large block of mass M shown in Figure P4.85 so that the...
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Hello!
I am looking for soltions to a question which has already been posted on your site I believe. Its from the text book Physics for Scientists and Engineers, Chapter 5 Laws of motion:
A block of mass 2.20 kg is accelerated across a rough surface by a rope passing over a pulley, as shown in figure P5.52. The tension in the rope is 10.0 N, and the pulley is 10.0 cm above the top of the block. The coefficient of kinetic friction is 0.400. A) Determine the acceleration of the block when x= 0.400 m. B) Find the value of x at which the acceleration becomes zero.
Thank you!!! ;o)
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