Hello I have to construct probability table using 3 coin toss and see how many head I can obtain.
I used tree diagram and go the probability and obtain
X (number of heads) |
P(X) |
0 |
1/8 |
1 |
3/8 |
2 |
3/8 |
3 |
1/8 |
Can you confirm that this is correct?
X (number of heads) |
P(X) |
X*P(X) |
(X-m)^{2}*P(X) |
0 |
0.125 |
0 |
0.28125 |
1 |
0.375 |
0.375 |
0.09375 |
2 |
0.375 |
0.75 |
0.09375 |
3 |
0.125 |
0.375 |
0.28125 |
Totals |
1 |
1.5 |
0.75 |
It is given that, 3 coins are tossed.
The possible outcomes are {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.
The formula for finding probability is shown below:
In this case, the probability of getting 0 heads is 1/8.
The probability of getting 1 head is 3/8.
The probability of getting 2 heads is 3/8.
The probability of getting 3 heads is 1/8...
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