# here is the link of table 8 https://www.webassign.net/podstat/peck_Appendix_A.pdfFrom the given information in each case below, state what you know about the P-value for a chi-square test and give the conclusion for a significance level of α = 0.01. Use Table 8 in Appendix A. (Enter your answers to three decimal places.)(a)    χ2 = 7.41, df = 2 ? < P-value <  ? Conclusion:Reject H0Fail to reject H0     (b)    χ2 = 12.88, df = 6?  < P-value <   ?Conclusion:Reject H0Fail to reject H0     (c)    χ2 = 17.71, df = 9? < P-value <   ?Conclusion:Reject H0Fail to reject H0     (d)    χ2 = 19.58, df = 4P-value   < ?Conclusion:Reject H0Fail to reject H0     (e)    χ2 = 6.09, df = 3P-value   >  ? Conclusion:Reject H0Fail to reject H0

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here is the link of table 8

https://www.webassign.net/podstat/peck_Appendix_A.pdf

From the given information in each case below, state what you know about the P-value for a chi-square test and give the conclusion for a significance level of α = 0.01. Use Table 8 in Appendix A.

(a)    χ2 = 7.41, df = 2
? < P-value <  ?

Conclusion:

Reject H0

Fail to reject H0

(b)    χ2 = 12.88, df = 6
?  < P-value <   ?

Conclusion:

Reject H0

Fail to reject H0

(c)    χ2 = 17.71, df = 9
? < P-value <   ?

Conclusion:

Reject H0

Fail to reject H0

(d)    χ2 = 19.58, df = 4
P-value   < ?

Conclusion:

Reject H0

Fail to reject H0

(e)    χ2 = 6.09, df = 3
P-value   >  ?

Conclusion:

Reject H0

Fail to reject H0

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Step 1

Note:

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Step 2

a)

Here, chi-square is 7.41. The degrees of freedom is 2. Given chi-square value is lies between 7.37 and 7.82 and corresponding p-values are 0.025 and 0.020 respectively. Thus, 0.020 < p-value < 0.025.

Decision rule:

If p-value ≤ α, then reject the null hypothesis. Otherwise, do not reject the null hypothesis.

Conclusion:

The level of significance is 0.01.

Here, p-value is greater than level of significance.

Therefore, fail to reject the null hypothesis.

b)

Here, chi-square is 12.88. The degr...

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