Hi, I am in physic I and they give me the problem The earth's radius is 6.37×106m; it rotates once every 24 hours. The angular speed is ω = 7.3×10−5 rad/s The speed of the point on the equator is v = 460 ms They want to know what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?) Please explain in detail how to get this because I asked before and the answer is wrong. I have one more try. Please help! Thank you!
Hi, I am in physic I and they give me the problem The earth's radius is 6.37×106m; it rotates once every 24 hours. The angular speed is ω = 7.3×10−5 rad/s The speed of the point on the equator is v = 460 ms They want to know what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?) Please explain in detail how to get this because I asked before and the answer is wrong. I have one more try. Please help! Thank you!
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter12: Rotation I: Kinematics And Dynamics
Section: Chapter Questions
Problem 62PQ: Problems 62 and 63 are paired. 62. C A disk is rotating around a fixed axis that passes through its...
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Hi, I am in physic I and they give me the problem
The earth's radius is 6.37×106m; it rotates once every 24 hours.
The angular speed is ω = 7.3×10−5 rad/s
The speed of the point on the equator is v = 460 ms
They want to know what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?)
Please explain in detail how to get this because I asked before and the answer is wrong. I have one more try. Please help!
Thank you!
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