Hi, the follwing code is return by value but I want to make it return by reference ... please help #include<iostream> using namespace std; double cubeValue (double n) {//function which takes parameter and cubes it double c = n * n * n; return c;//return by value } int main () {//main function double number; cout << "Enter the number you wish to cube: "; cin >> number; double n = cubeValue (number);//calling function and storing return by value in n cout << "The number after cubing is: " << n << endl; }
Hi, the follwing code is return by value but I want to make it return by reference ... please help #include<iostream> using namespace std; double cubeValue (double n) {//function which takes parameter and cubes it double c = n * n * n; return c;//return by value } int main () {//main function double number; cout << "Enter the number you wish to cube: "; cin >> number; double n = cubeValue (number);//calling function and storing return by value in n cout << "The number after cubing is: " << n << endl; }
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter7: User-defined Simple Data Types, Namespaces, And The String Type
Section: Chapter Questions
Problem 1TF
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Hi, the follwing code is return by value but I want to make it return by reference ... please help
#include<iostream>
using namespace std;
double cubeValue (double n)
{//function which takes parameter and cubes it
double c = n * n * n;
return c;//return by value
}
int
main ()
{//main function
double number;
cout << "Enter the number you wish to cube: ";
cin >> number;
double n = cubeValue (number);//calling function and storing return by value in n
cout << "The number after cubing is: " << n << endl;
}
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