High performance liquid chromatography analyzed a sample mixture and it has been found thecomposition as below. The density of the sample is 480 Kg/m3CO212%N2028%co30%H2SO430%i)If the sample flows at the rate of 1200 Kg/h. Calculate the volumetric flowrate.ii)Calculate the mass of 125 ml of the gas.iii)How many gallons of the sample, will be delivered by pump in half an hour?

Answered: High performance liquid chromatography…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Question

High performance liquid chromatography analyzed a sample mixture and it has been found the
composition as below. The density of the sample is 480 Kg/m3
CO2
12%
N20
28%
co
30%
H2SO4
30%
i)
If the sample flows at the rate of 1200 Kg/h. Calculate the volumetric flowrate.
ii)
Calculate the mass of 125 ml of the gas.
iii)
How many gallons of the sample, will be delivered by pump in half an hour?

Expert Solution

Step 1

Given,

density of the mixture, $ρ = 480 Kg / m^{3}$

(i)

mass flow rate of the mixture, $\dot{m} = 1200 Kg / h$

Calculate the volumetric flow rate of the mixture as follows:

$\dot{V} = \frac{\dot{m}}{ρ} \dot{V} = \frac{1200 Kg / h}{480 Kg / m^{3}} \dot{V} = 2.5 m^{3} / h$

Therefore, the required solution is $2.5 m^{3} / h$ .

Step 2

(ii)

Density of a substance is defined as the ratio of mass of the substance to the volume of substance.

$Density = \frac{mass}{volume}$

Volume of the gas is $125 mL$ .

Calculate the mass of the gas as follows:

$Density of gas = \frac{mass of gas}{volume of gas} mass of gas = 480 \frac{Kg}{m^{3}} \times 125 mL \times \frac{1 m^{3}}{1000 L} \times \frac{1 L}{1000 mL} mass of gas = 0.06 Kg$

Therefore, the required solution is $0.06 Kg$ .

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