Question
Asked Sep 12, 2019

how do i find the total mass of percipitated product produced in a reaction where i have 50 ml sample of .150 M NaOH is added to 20.0 mL of .250 M NiBr2? step by step please 

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Step 1

We have to calculate the mass of the product that forms when 50 ml sample of 0.150 M NaOH is added to 20.0 mL of 0.250 M NiBr2.

Step 2

Nickel bromide reacts with NaOH to form the precipitate of nickel hydroxide.

NiBr (aq)2NaOH(aq)Ni(OH), (s)+2NaBr(aq)
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NiBr (aq)2NaOH(aq)Ni(OH), (s)+2NaBr(aq)

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Step 3

Calculate the moles of reactants, NiBr2 and NaOH, using their molarity and volume.

Molarity of NiBr2= 0.250 M

Volume of NiBr2 solution= ...

Moles of solute
Molarity
Volume of solution in L
Moles of NiBr
:. Molarity of NiBI
Volume of solution in L
Moles of NiBr
0.250 M
0.020L
Moles of NiBr, = 0.250 M x0.020 L- 0.005 moles
and
Moles of NaOH
Molarity of NaOH
Volume of solution in L
Moles of NaOH
0.150 M
0.050L
Moles of NaOH 0.150 M x 0.050 L
0.0075 moles
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Moles of solute Molarity Volume of solution in L Moles of NiBr :. Molarity of NiBI Volume of solution in L Moles of NiBr 0.250 M 0.020L Moles of NiBr, = 0.250 M x0.020 L- 0.005 moles and Moles of NaOH Molarity of NaOH Volume of solution in L Moles of NaOH 0.150 M 0.050L Moles of NaOH 0.150 M x 0.050 L 0.0075 moles

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