Asked Sep 20, 2019

How do you solve 5x^2+7x=4x^2+x-18?


Expert Answer

Step 1

First take all the terms on one side of the “equal” sign and “zero” on the other side, it gives

5x27x 4x2 + x -18
5x27x-4x2-x+18 = 0
x6x18 0

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5x27x 4x2 + x -18 5x27x-4x2-x+18 = 0 x6x18 0

Step 2

Comparing the equation with the standard form of quadratic equation:
ax2 + bx + c = 0,
It gives a = 1, b = 6, c = 18  

Step 3

Using the quadratic formula to obtai...

x =

Image Transcriptionclose

-bb-4ac x = 2a


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