Question
Asked Sep 21, 2019
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How many atoms of oxygen are contained in 47.6 g of Al2(CO3)3? The molar mass of Al2(CO3)is 233.99 g/mol.

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Expert Answer

Step 1

Given,

Mass of Al2(CO3)3 = 47.6 g

Molar mass of Al2(CO3)= 233.99 g/mol

Number of moles of Al2(CO3)can be calculated as:

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Mass MolesMolar mass 47.6 g Moles233.99 g/mol Moles 0.203 mol

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Step 2

1 mol of Al2(CO3)contains 3×3 = 9 mol of oxygen. Therefore, moles of oxygen in 0.203 mol of Al2(CO3)can be calculated as :

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9 mol oxygen 1 mol Al2(CO3)3 contains 9 mol oxygen x 0.203 mol Al2(CO3)3 .. 0.203 mol Al2(CO3)3 contains 1 mol Al2(CO3)3 = 1.827 mol oxygen

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Step 3

The number of atoms of in 1.827 mol o...

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6.022 x 1023 atoms 1 mol contains 6.022 x 1023 atoms x 1.827 mol . 1.827 mol contains 1 mol 1024 atoms = 1.10 x

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Chemistry