Question
Asked Oct 6, 2019

How many F minus ions will one PB+ ion be paired? 1, 2, 3 , or 4?

check_circleExpert Solution
Step 1

Fluorine (F) is a chemical element with atomic number 9. Its electronic configuration is 1s2 2s2 2p5 and it has 7 electrons in its valence shell. To get octet configuration it gain or share 1 electron.

Lead (Pb) is a chemical element with atomic number 82. Its electronic configuration is [Xe] 4f14 5d10 6s2 6p2 and it has 4 electrons in its valence shell. It can show +2 and +4 oxidation state.

Step 2

Formation of PbF2...

Pb losses 2 electron and forms Pbt2 cation
PbPb+22e
These 2 electrons are gain by 2 fluorine atoms and forms (2F) Anion
2F 2e 2F
Due to electrostatic force of attraction between cation and
anion, both ions get attracted towards each other forms ionic bond.
Pb Pb+22e
+ z6=
2F
2F
Pb
2F Pb+2 2F
PbF2
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Pb losses 2 electron and forms Pbt2 cation PbPb+22e These 2 electrons are gain by 2 fluorine atoms and forms (2F) Anion 2F 2e 2F Due to electrostatic force of attraction between cation and anion, both ions get attracted towards each other forms ionic bond. Pb Pb+22e + z6= 2F 2F Pb 2F Pb+2 2F PbF2

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