Question
Asked Oct 6, 2019

How many grams of Ag2CrO4 can be produced from 1.200 grams of AgNO3?

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Expert Answer

Step 1

Given,

Number of grams of AgNO3 is 1.200 grams.

The equation for the formation of silver chromate is:

 

>Ag,CrO4(s)2NaNO3(aq)
2AgNO3(a)Na2CrO4(aq)
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>Ag,CrO4(s)2NaNO3(aq) 2AgNO3(a)Na2CrO4(aq)

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Step 2

So two moles of silver nitrate is needed to produce on mole of silver chromate.

Therefore one mole of silver nitrate is needed to produce half mole of silver chromate.

Massin gram
Numberof moles of AgNO3 Molarmass ofAgNO3
1.200 grams 0.00 706 mol
169.87g/mol
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Massin gram Numberof moles of AgNO3 Molarmass ofAgNO3 1.200 grams 0.00 706 mol 169.87g/mol

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Step 3

Therefore number of moles of s...

Number of molesof Ag , CrO=
x 0.007 06 mol =0.00353 mol
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Number of molesof Ag , CrO= x 0.007 06 mol =0.00353 mol

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