Asked Oct 25, 2019

How many grams of glucose (C6H12O6) are present in 7.8 L of a 1.3 M glucose solution?


Expert Answer

Step 1

Number of grams of glucose has to be calculated.


Volume = 7.8 L

Molarity = 1.3 M

Molar mass of glucose = 180.2 g/mol


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The Molarity of the solution can be calculated by using following formula Number of moles ofsolute Molarity of the solution Volumeof solution in litre

Step 2

Number of moles of gluco...


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Number of moles is calculated as follow Number of moles Molarity of the solution x Volume of solution in litre Number of moles =1.3 Mx7.8 L Number of moles 10.14


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