How many grams of KOH are needed to neutralize 800 mL of 0.75 M HNO3

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ChapterU4: Toxins: Stoichiometry, Solution Chemistry, And Acids And Bases
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How many grams of KOH are needed to neutralize 800 mL of 0.75 M HNO3

Expert Solution
Step 1

The chemical equation may be written as:

KOH+HNO3KNO3+H2O

Given data is:

Concentration of HNO3 = 0.75 M

Volume used = 800 mL=800×10-3L

Now, 

Number of moles = concentration×volume=0.75M×800×10-3L=0.6moles

 

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