How many liters of pure water will be required to disslove 0.885g of solid lead iodate, if the water already intially contains 0.135 M Pb(NO3)2

Q: II. Von Weirm an ratio. Fill in the Blanks With the given conditions during precipitation, conclude…

A: van-Weirman ratio is expressed as: Relative supersaturation=Q-SS                  (1)where,Q:…

Q: Consider the reaction of 75.0 mL of 0.350 M CSHSN (Kb = 1.7 x 10) with 100.0 mL of 0.419 M HCI.…

A: In the given reaction,  75.0 mL of 0.350 M C5H5N reacts with 100.0 mL of 0.419 M HCI.  Kb = 1.7 x…

Q: Solid ammonium carbonate is slowly added to 125 mL of a 0.0682 M iron(II) acetate solution. The…

A:

Q: Solid ammonium carbonate is slowly added to 125 mL of a 0.0458 M copper(II) nitrate solution. The…

A: Since copper (II) carbonate is insoluble in water. Hence when ammonium carbonate i.e (NH4)2CO3 is…

Q: Solid zinc nitrate is slowly added to 175 mL of a 0.0377 M sodium hydroxide solution. The…

A:

Q: 6.A 16.6 mL aliquot of 0.2 M aqueous hydrochloric acid is titrated with 0.6 M NaOH (ac). What volume…

A: Given that: volume of HCl = 16.6 mL molarity of HCl = 0.2 M molarity of NaOH = 0.6 M  To find, the…

Q: Solid ammonium phosphate is slowly added to 150 ml of a 0.0595 M aluminum nitrate solution. The…

A: Ammonium Phosphate react with Aluminium Nitrate to form a solid precipitate of Aluminiun Phosphate.

Q: What is the nitrate ion concentration in the final solution when 50mL of 0.5M NaNO3 is mixed with…

A: The concentration of solute in the given solution is given in the term of molarity.

Q: How many mL of 0.150 M HCI are needed to react with 24.0 mL of 0.450 M NaOH ? HCl(ag) + NAOH(ag) →…

A: We have to find volume of HCl solution for complete neutralisation

Q: A 15.5 mL sample of a solution Sr(OH)2 is titrated to the equivalence point with 65.2 mL of 0.7807 M…

A: Acids and bases neutralize each other. Strontium hydroxide will neutralize hydrochloric acid to…

Q: Solid ammonium iodide is slowly added to 150 ml of a 0.0390 M silver nitrate solution. The…

A: We have to use the concept of solubility product. From the standard table we will refer the…

Q: Calculate [HgCl4 2−] in a solution prepared by adding 0.0200 mol of NaCl to 0.250 L of a 0.100-M…

A: Assuming complete ionization of both HgCl2 and NaCl

Q: pH Titration A student is titrating 150.0 mL cid is 3 85) with a 0 250 M solution of NaC

A: Given, pKa = 3.85 Thus ,ka = 10-3.85                  = 0.000141253754      Kb = 7.07945787×10-11 .…

Q: Solid ammonium sulfide is slowly added to 125 mL of a 0.0634 M copper(Il) acetate solution. The…

A:

Q: It required 11.96 mL of 0.102 M NaOH to titrate a 0.0927 g sample of an unknown monoprotic acid to…

A: Calculate the moles of NaOH,          (0.102 mol/L) (0.01196 L) = 0.00121992 mol

Q: If you have a solution containing AgNO3 and Ni(NO3)2, how can you separate them with selective…

A: Applying concept of separation by using precipitation method.

Q: A 10.00 mL sample of a solution of hydrofluoric acid, HF, is diluted to 500.00 mL. Of this, 20.00 mL…

A: The chemical reaction is,  Calculate the diluted morality of HF, HF=13.51×10-3 L NaOH20 ×10-3…

Q: How will the following sitations affect the final calculation of the molarity of HC2H3O2? The end…

A: Surpassing the end point of any titration is known as overshooting.

Q: Lläi 4 If 20mL of a 0.40M Mg(OH)2 solution is used to titrate 25mL of HCI solution, * ? the molarity…

A: The chemical reaction for this will be  Mg(OH)2 + 2HCl - - - - - - - > 2H2O+ Mgcl2 According to…

Q: If 0.626 g of an unknown monoprotic acid was used to prepare a 25.00 mL weak acid solution and this…

A:

Q: Solid barium acetate is slowly added to 125 mL of a 0.0558 M sodium chromate solution. The…

A: Molarity  = 0.0558M Given volume of milliliter change a liter  Volume of liter 125 ×10-3 liter  We…

Q: Calculate the concentration of sulfate ion when BaSO4 just begins to precipitate from a solution…

A:

Q: Solid sodium carbonate is slowly added to 150 mL of a 0.0504 M iron(II) acetate solution. The…

A:

Q: When titrating a 0.4444 g sample of KHP (molar mass = 204.2 g/mol), it took 18.54 mL of sodium…

A:

Q: a) Sulfuric acid solution is standardized by titrating with 0.678 g of primary standard sodium…

A:

Q: When 10.23 ml of an unknown weak acid was titrated, it required 12.08 mL of 0.423M NaOH to reach the…

A: Given that : Volume of NaOH (V1) = 12.08 mL Molarity of NaOH (M1) = 0.423 M Volumes of weak acid…

Q: Solid copper(II) acetate is slowly added to 150 mL of a 0.0599 M sodium sulfide solution. The…

A: Chemical equation:    Na2S(aq) + Cu(CH3COO)2(aq) = Na(CH3COO)(aq) + CuS (S) Here CUS is the…

Q: An unknown acid salt was dissolved in water and titrated with 0.105 M NaOH. If 1.20 grams of the…

A: A stage achieved during titrations where equivalents of both reactants are same and full…

Q: The solubility of Pb(OH)2 is 78 mg/500. mL. Calculate the Ksp for lead (II) hydroxide

A: We have to calculate the Ksp for given salt.

Q: Solid sodium bromide is slowly added to 175 mL of a 0.0318 M silver acetate solution. The…

A: Given data,Molarity of CH3COOAg=0.0318MVolume of CH3COOAg=175mL

Q: Solid zinc nitrate is slowly added to 175 mL of a 0.0572 M potassium sulfide solution. The…

A: Here we are required to find the concentration of zinc which is needed to just initiate the…

Q: I have a 50.0 mL sample of a solution of hydrocyanic acid, HCN, of unknown concentration. I titrate…

A: Given : Concentration of NaOH = 10.0 M Volume of NaOH solution required to reach endpoint = 6.50 mL…

Q: Potassium hydrogen phthalate (KHP) is often used as a primary standard in acid–base titrations. If…

A: Given information: Volume of NaOH = 19.45 mL Gram of KHP = 0.397 g

Q: Solid potassium hydroxide is slowly added to 50.0 mL of a 0.329 M manganese(II) bromide solution…

A: According to the chemical equation, shown by equation (1), the number of mole of manganese(II)…

Q: Solid nickel(II) nitrate is slowly added to 75.0 mL of a 0.0636 M ammonium carbonate solution. The…

A: Note: As per the guidelines, solution of first question has been made. For the expert solution of…

Q: it took 32.47 mL of 0.123M NaOH to reach the endpoint when titrating a sample containg 0.2372g of…

A: Since the acid is given as triprotic  hence the moles of NaOH required to reach the endpoint = moles…

Q: To 0.360 L of 0.150 M NH 3 H is added 0.140 LL of 0.110 M MgCl 2.

A: first calculate the moles of every compound used n(NH3)= (0.150 mol/L )(0 .360 L) = 0.054 moles NH3…

Q: Solid lead acetate is slowly added to 125 mL of a 0.0470 M ammonium bromide solution. The…

A: Given Concentration of ammonium bromide = 0.0470 M

Q: What are the concentrations of ([H+], [OH-], [NH3+],[NH+4]) in the final solution when mixed 10mL of…

A: The concentration of the given species can be obtained by the balanced chemical reaction of NH3 with…

Q: 17.A 16.6 mL aliquot of 0.2 M aqueous hydrochloric acid is titrated with 0.6 M NaOH (ac). What…

A:

Q: 100.0 mL of 0.500 M CaBr2 and 50.0 mL of 1.00 M NaBr are mixed. What is the concentration of bromide…

A: Molarity is defined as no.of moles of solute divided by volume of solution in liter .

Q: Solid ammonium fluoride is slowly added to 175 mL of a 0.0682 M lead nitrate solution. The…

A: From the given data we have Ksp of PbF2=3.7×10-8 Upon addition of ammonium fluoride  Lead fluoride…

Q: 2. Solid lead(II) cyanide is slowly added to 125 mL of a 0.497 M ammonium phosphate solution until…

A:

Q: A 0.345 gram sample of potassium hydrogen phthalate is titrated to equivalence point with 18.15 mL…

A: Potassium hydrogen phthalate is a monoprotic acid with molecular formula C8H5KO4  Hence the reaction…

Q: Solid ammonium carbonate is slowly added to 150 mL of a 0.0645 M magnesium acetate solution. The…

A:

Q: Solid sodium sulfite is slowly added to 175 mL of a 0.0435 M barium acetate solution. The…

A: Dissolution of any ionic compound in a known solution causes the establishment of equilibrium…

Q: A 25.00 mL sample of H2SO4 requires 31.43 mL of 0.110 M NaOH to reach the equivalence point. What is…

A: Amount of solute required can be determined from molarity. Now, mole of NaOH can be determined as,…

Q: Solid sodium fluoride is slowly added to 150 mL of a 0.0548 M magnesium acetate solution. The…

A:

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.