Question
Asked Sep 12, 2019
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how many milliliters of .05000 M Ca(OH)2 or .05000 M HNO3 would be required to neutralize the solution left after mixing. you have 50mL sample of Ca(OH)2 and 20 mL of HNO3 

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Expert Answer

Step 1

The values are given as follow:

Concentration of Ca(OH)
= 0.05000 M
Concentration of NH, = 0.05000 M
Volume of Ca(OH) = 50 mL
Volume of NH, 20 mL
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Concentration of Ca(OH) = 0.05000 M Concentration of NH, = 0.05000 M Volume of Ca(OH) = 50 mL Volume of NH, 20 mL

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Step 2

The balanced equation can be written as follows:

Ca (OH)+2HNO,Ca(NO,), +2H,O
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Ca (OH)+2HNO,Ca(NO,), +2H,O

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Step 3

Molarity expressed as number of moles of solute per liters of solution. It describes the ...

n
м
Here
n=moles of solute
v=volume
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n м Here n=moles of solute v=volume

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