Question
Asked Oct 21, 2019
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How many milliliters of 12.0 M HCl(aq) are needed to prepare 315.0 mL of 1.00 M HCl(aq)?

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Expert Answer

Step 1

Given, M1 = 1.00M HCl

            M2 = 12.0M HCl

            V1 = 315.0mL

            V2 = ?

Step 2

The volume can be c...

Mу-м,V,
М;
M,V
М,
1.00Мx315.0mL
12.0М
26.25 mL
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Mу-м,V, М; M,V М, 1.00Мx315.0mL 12.0М 26.25 mL

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