How many milliliters of a 0.222 M HI solution are needed to reduce  21.5 mL of a 0.357 M KMnO4 solution according to the following equation:   10HI + 2KMnO4 + 3H2SO4 → 5I2 + 2MnSO4 + K2SO4 + 8H2O

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Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.92QP: How many milliliters of 0.250 M KMnO4 are needed to react with 3.55 g of iron(II) sulfate, FeSO4?...
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How many milliliters of a 0.222 M HI solution are needed to reduce 

21.5 mL of a 0.357 M KMnO4 solution according to the following equation:
 
10HI + 2KMnO4 + 3H2SO4 → 5I2 + 2MnSO4 + K2SO4 + 8H2O
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