Question
Asked Oct 1, 2019
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How many mL of 0.715 M HCl are needed to dissolve 7.44 g of MgCO3?

2HCl(aq) + MgCO3(s) MgCl2(aq) + H2O(l) + CO2(g)

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The balanced chemical equ...

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2HCI MgCO эMgClya) + Н,0, + со, 3(s) 2(E) (aq) (1) Moles of MgCO3 =7.44 gxmolMgCO3 =0.088mol 84.3139 g 2mol HC Moles of HCl 0.088molMgCO3 -0.176mol 1mol Mg CO

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