How many mL of 6.00 ppm solution are needed to make 4.00 L of a 0.100 ppm solution ? (answer = 66.7 mL) What is the dilution factor ? (answer = 1:60)

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Chapter7: Solutions And Colloids
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How many mL of 6.00 ppm solution are needed to make 4.00 L of a 0.100 ppm solution ? (answer = 66.7 mL)

What is the dilution factor ? (answer = 1:60)

Question 6 of 10
1 Points
1. How many mL of a 6.00 ppm solution are needed to make 4.00 L of a 0.100 ppm solution ?
First, we have to identify the variables
Cc =
ppm
CD =
ppm
Vc = ?
Vo =
first put symbols, then put numbers
ppm)(
L)
Vc =
L
mL
mL
L
2. What is the dilution factor ?
first put symbols, then put numbers
CD
1
dilution =
ii
00
CC
а. 36.00
b. 5.00
С. 31.00
d. 150.0
е. 12
f. 350.00
g. 125,0
h. 2.4 x 10-2
i. 1.2 x 103
j. 1.786
k. 7.143
I. 25.00
m. 7.500
n. 100.0
o. 500.0
р. 15.00
q. 185.00
r. 444.44
S. 2.00 x 103
t. 20.67
u. 0.500
v. 499,5
w. 15
х. 33.33
у. 1.00 х 105
z. 10.0
aа. 1.00
bb. 106
сс. 6.00
dd. 6.00 x 105
ее. 6.00 х 106
ff. 20.0
gg. 200.
hh. 1.20 x 106
ii. 60
j. 0.100
kk. 4.00
II. 103
mm. 0.0667
nn. 66.7
00. Cc
pp. Vc
qq. VD
rr. Cp
V Mark for Review What's This?
Transcribed Image Text:Question 6 of 10 1 Points 1. How many mL of a 6.00 ppm solution are needed to make 4.00 L of a 0.100 ppm solution ? First, we have to identify the variables Cc = ppm CD = ppm Vc = ? Vo = first put symbols, then put numbers ppm)( L) Vc = L mL mL L 2. What is the dilution factor ? first put symbols, then put numbers CD 1 dilution = ii 00 CC а. 36.00 b. 5.00 С. 31.00 d. 150.0 е. 12 f. 350.00 g. 125,0 h. 2.4 x 10-2 i. 1.2 x 103 j. 1.786 k. 7.143 I. 25.00 m. 7.500 n. 100.0 o. 500.0 р. 15.00 q. 185.00 r. 444.44 S. 2.00 x 103 t. 20.67 u. 0.500 v. 499,5 w. 15 х. 33.33 у. 1.00 х 105 z. 10.0 aа. 1.00 bb. 106 сс. 6.00 dd. 6.00 x 105 ее. 6.00 х 106 ff. 20.0 gg. 200. hh. 1.20 x 106 ii. 60 j. 0.100 kk. 4.00 II. 103 mm. 0.0667 nn. 66.7 00. Cc pp. Vc qq. VD rr. Cp V Mark for Review What's This?
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