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How many moles of compound are in 23.3 g of Na2B407 10H2O? mol The number of significant digits is set to 3; the tolerance is +/-2%

How many moles of compound are in 23.3 g of Na2B407 10H2O? mol The number of significant digits is set to 3; the tolerance is +/-2%

Fundamentals Of Analytical Chemistry
Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter4: Calculations Used In Analytical Chemistry
Section: Chapter Questions
Problem 4.4QAP
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How many moles of compound are in 23.3 g of Na2B4O7·10H2O?

How many moles of compound are in 23.3 g of Na2B407-10H2O? mol The number of significant digits is set to 3; the tolerance is +/-2%
Transcribed Image Text:How many moles of compound are in 23.3 g of Na2B407-10H2O? mol The number of significant digits is set to 3; the tolerance is +/-2%
Expert Solution
Step 1

Mass of Na2B4O7·10H2O= 23.3 g

Element  Atomic mass
Na 22.989770
B 10.811
O 15.9994
H 1.00794

 

The molar mass of Na2B4O7·10H2O=22.98977 x 2 + 10.811 x 4 + 15.9994 x 7 + 10 x (1.00794 x 2 + 1 x 15.9994)

The molar mass of Na2B4O7·10H2O=381.3721 g/mol

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