Question
Asked Sep 26, 2019
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How many revolutions per min would a 25-m-diameter ferris wheel need to make for the passengers to feel "weightless" at the topmost point? 

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Expert Answer

Step 1

The passengers weight is equal to the centripetal force is related by the equation.

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mg r mg r

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Step 2

Substitute the values,

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(9.80m/s2) 25m 2 |(9.80m/s2) (12.5m) = 0.885rad/s

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Step 3

Convert the radian per second in...

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radIrev 2xad lmin 60s a0.885 =8.46rev/min

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