How much 53,5mM potassium hydroxide is needed to bring 47,0mL of a 110,mM solution of dimethylanilinium chloride (pK,= 5,20) to a pH of 4,9. The initial pH of the acid solution is 3,1. less than 10mL between 10 and 15ml O between 15 and 20mL O between 20 and 25mL O between 25 and 30mL O between 30 and 35mL O between 35 and 40mL between 40 and 45mL between 45 and 50mL more than 50mL

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter15: Acid–base Equilibria
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How much 53,5mM potassium hydroxide is needed to bring
47,0mL of a 110,mM solution of dimethylanilinium chloride
(pK = 5,20) to a pH of 4,9. The initial pH of the acid solution is
3,1.
O less than 10mL
between 10 and 15ml
O between 15 and 20mL
between 20 and 25mL
between 25 and 30mL
O between 30 and 35mL
O between 35 and 40mL
between 40 and 45mL
O between 45 and 50mL
more than 50mL
Transcribed Image Text:How much 53,5mM potassium hydroxide is needed to bring 47,0mL of a 110,mM solution of dimethylanilinium chloride (pK = 5,20) to a pH of 4,9. The initial pH of the acid solution is 3,1. O less than 10mL between 10 and 15ml O between 15 and 20mL between 20 and 25mL between 25 and 30mL O between 30 and 35mL O between 35 and 40mL between 40 and 45mL O between 45 and 50mL more than 50mL
Expert Solution
Step 1

The molarity of potassium hydroxide is 53.5 mM. The volume of 110 mM dimethylanilinium is 47.0 mL. The initial and the final pH of acid solution is 3.1 and 4.9, respectively. The pKa of dimethylanilinium is 5.20.

Step 2

Convert 53.5 mM to M.

53.5 mM=53.51000 M=0.0535 M

Convert 110 mM to M.

110 mM=1101000 M=0.11 M

Assume the volume of KOH added is V.

The number of moles of 47.0 mL of 0.11 M dimethylanilinium is calculated as,

n1=47.01000 L×0.11 mol L-1=5.17×10-3 mol

The number of moles of 0.0535 M KOH is calculated as,

n2=0.0535 M×V=0.0535V mol

Step 3

The general chemical reaction between KOH and dimethylanilinium is expressed as,

Dimethylanilinium+KOHSalt+H2O

The above reaction shows that the molar ratio between KOH and dimethylanilinium is 1 : 1. KOH is the limiting reactant.

The ICE table is expressed as,

  Dimethylanilinium + KOH Salt + H2O
I (mol) 0.00517   0.0535V   0   0
C (mol) -0.0535V   -0.0535V   +0.0535V   +0.0535V
E (mol) 0.00517-0.0535V   0   0.0535V   0.0535V
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