Question
Asked Dec 25, 2019
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How much energy is required to change a 40.-g ice cube from ice at -10.°C to steam at 110.°C?

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Expert Answer

Step 1

Write the expression to find the energy required to convert -10.0°C ice to 0°C and substitute the values,

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тс.ДТ ice 10 kg ( 2090 J/kg - °C)((0°C)-(-10.0°C)) 1g =(40 g) = 836 J

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Step 2

Write the expression to find the energy required to convert 0°C ice to 0°C water and substitute the values,

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Qes = mL; ice (10* kg (3.33×10³ J/kg) = (40 g) 1g =13320 J

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Step 3

Write the expression to find the energy required to convert ...

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O = mc_AT (10 kg (4186 J/kg· °C)((100°C)-(0.0°C)) 1g =(40 g) =16744 J

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