Question
Asked Sep 18, 2019
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How much work does an ideal Carnot refrigerator require to remove 1.60 J of energy from liquid helium at 3.80 K and expel this energy to a room-temperature (293-K) environment?

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Step 1

Co-efficient of performance is,

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Tо СОР Тн — Т. 3.80K 293K-3.80K 0.0131

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Step 2

Work done ...

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Energyremoved COP 1.60J 0.0131 =122.14J

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Heat Transfer

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