Question
Asked Sep 15, 2019
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How would you prepare 10 mL of a 0.25% m/v HCl solution if 1% m/v HCl was available? How much 1% m/v HCl is needed? How much distilled water is used?

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Expert Answer

Step 1

It is given that:

Volume (V1) of solution = 10 mL

Concentration of HCl solution (M1) = 0.25 %

Concentration of available solution of HCl (M2) = 1 %

Step 2

Law of equivalence states that the volume of titrants reacted have same number of equivalents points at the end point of titration. The expression for this is given as follows:

M,V MV
where, M,is the concentration of the solution
Vis the volume of solution
M2is the concentration of new solution
V,is the volume of new solution
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M,V MV where, M,is the concentration of the solution Vis the volume of solution M2is the concentration of new solution V,is the volume of new solution

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Step 3

Now using law of equivalence equation, the volume o...

MV,3м,V,
0.2510 mL1%xV
V2-2.5 mL
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MV,3м,V, 0.2510 mL1%xV V2-2.5 mL

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