Question

Asked Sep 15, 2019

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How would you prepare 10 mL of a 0.25% *m/v* HCl solution if 1% *m/v* HCl was available? How much 1% *m/v* HCl is needed? How much distilled water is used?

Step 1

It is given that:

Volume (V_{1}) of solution = 10 mL

Concentration of HCl solution (M_{1}) = 0.25 %

Concentration of available solution of HCl (M_{2}) = 1 %

Step 2

Law of equivalence states that the volume of titrants reacted have same number of equivalents points at the end point of titration. The expression for this is given as follows:

Step 3

Now using law of equivalence equation, the volume o...

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