Human body temperatures are normally distributed with a mean of 98.20F and a standard deviation of 0.62F. Find the temperature that separates the top 7% from the bottom 93%. Round to the nearest hundredth of a degree.  Find the indicated probability, showing an appropriate calculator sequence.

Question
Asked Oct 18, 2019
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Human body temperatures are normally distributed with a mean of 98.20F and a standard deviation of 0.62F. Find the temperature that separates the top 7% from the bottom 93%. Round to the nearest hundredth of a degree. 

 

Find the indicated probability, showing an appropriate calculator sequence.

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Expert Answer

Step 1

It is given that the mean and standard deviation are 98.20 and 0.62, respectively.

Step 2

The area of 0.07 to the right of z is 1.48 using standard normal table.

 

The temperature that separated the top 7% from the bottom 93% is obtained as follows:

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