I 4 2 3 1 II #a 9 10 8 5 7 6 3 II 2 2 10 3 6 4 5 IV 1 3 6 7 8 2 5 9 8. If individuals IV-3 and IV-4 marry, what is the probability that their first child will have the disease? С. 1/64 Е. 1/16 А. 1/32 D. 1/12 B. 1/48 110! 9. Statistically, this trait has a probability of 0.0001 in the population in which these families live. If IV5 is married with a man who is also in this community. What is the probability if your first child has this trait? E. 0.246% B. 0.0413% C. 0.165% D. 0.123% A. 0.0825% 10. If the disease is inherited as an autosomal dominant trait with 50% penetrance, then what would be the possibility that the first child from the marriage of IV3 and IV4 shows this disease? A 1.0 B. 0.0417 E. None of the C. 0.0313 D. 0.1342 answers. CO --IN о

I 4 2 3 1 II #a 9 10 8 5 7 6 3 II 2 2 10 3 6 4 5 IV 1 3 6 7 8 2 5 9 8. If individuals IV-3 and IV-4 marry, what is the probability that their first child will have the disease? С. 1/64 Е. 1/16 А. 1/32 D. 1/12 B. 1/48 110! 9. Statistically, this trait has a probability of 0.0001 in the population in which these families live. If IV5 is married with a man who is also in this community. What is the probability if your first child has this trait? E. 0.246% B. 0.0413% C. 0.165% D. 0.123% A. 0.0825% 10. If the disease is inherited as an autosomal dominant trait with 50% penetrance, then what would be the possibility that the first child from the marriage of IV3 and IV4 shows this disease? A 1.0 B. 0.0417 E. None of the C. 0.0313 D. 0.1342 answers. CO --IN о

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter18: Genetics Of Behavior

Section: Chapter Questions

Problem 14QP: A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known...

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I need help in table 2 & 3 please Table 1 Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 433.875 129.875 16789.68 38.69 Disease, Female 267 433.875 166.875 26855.01 61.89 WT, Male 285 144.625 140.375 19705.14 136.25 WT, Female 301 144.625 156.375 24453.15 156.37 Total 1157 1157 393.20 DF 3 p-value 7.84 Expected progencies as per SLR MOI’s = 1:1 for both male and female Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 289.25 14.75 217.56 0.75 Disease, Female 267 289.25 22.25 495.06 1.85 WT, Male 285 289.25 4.25 18.06 0.06 WT, Female 301 289.25 11.75 138.06 0.46 Total 1157 1157 3.12 DF 3 p-value 7.84 Progenies are following SR MOI’s that parents have genotypes and progenies in ratio 1:1 In Table 2,…
Cystic fibrosis is an autosomal recessive disorder that affects 1 in 3 000 newborns with Caucasian background. It causes thick mucus build up in various organs and can cause damages and problems in respiratory and digestive systems. a) What is the frequency of the cystic fibrosis allele in the Caucasian population? Show all your work and express your answer as a value between 0 and 1 rounded to two decimal places. b) What percentage of the Caucasian population would be carriers for cystic fibrosis? Show all your work and express your answer rounded to two decimal places. c)If two individuals are carriers of the cystic fibrosis allele, what is the probability that they would have a girl without cystic fibrosis? Show all your work (including the Punnett square) and express your answer as a value between 0 and 1 rounded to two decimal places.
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What is the frequency of the aa genotype if the frequencies of AA & Aa are 0.1900 and 0.3600?
If the frequency of those exhibiting a monogenic autosomal recessive phenotype caused by a rare clinically relevant allele is 1/9250 in a given population, what is the carrier frequency? Please give your answer as a percentage to 3 decimal places, do not include the % symbol.
Please read the scenario below, and then answer the question (in bold) that follows. Tay-Sachs disease is a fatal autosomal recessive disorder in children (usually by age 5) that causes a progressive degeneration of the central nervous system. This disease affects 1 in 3,500 newborns of European Ashkenazi Jewish ancestry in the U.S. population. What is the number of carriers in the population? a. 1 person b. 60 persons c. 116 persons d. 3,383 persons e. 3,441 persons
As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progeny
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The recessive allele that causes Ellis– van Creveld syndrome when homozygous has a frequency of about 0.07 in the Amish population of Pennsylvania, although its frequency is only about 0.001 in the generalpopulation. How many persons out of one thousand in the Amish population would be expected to have the disease? How many out of one million in the general population?
Consider the case of a hypothetical genetic disease called WhySciEleven (WSE), an inherited disease that results to the inability to complete production of an amino acid “moduleactivity” that results in brain damage if untreated. WSE is due to a recessive allele. Given one WSE occurrence per 10,000 births. Which term in the Hardy-Weinberg equation corresponds to the frequency of individuals who have no alleles for the disease WSE? a. p b. 2pq c. p2 d. q2
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Tay–Sachs disease is an autosomal recessive disorder. Among Ashkenazi Jews, the frequency of Tay–Sachs disease is 1 in 3600. Assuming the Ashkenazi population is in Hardy-Weinberg equilibrium, what proportion of the population is expected to be carriers (e.g. heterozygous) for the Tay–Sachs allele?