I am confused about how to find the confidence interval (at the 90% level) of the remaining data points on part C. Which then leads to not being able to figure out part D to find that higher level of confidence.

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I am confused about how to find the confidence interval (at the 90% level) of the remaining data points on part C. Which then leads to not being able to figure out part D to find that higher level of confidence.

I attached the chart of confidence levels for these questions. Thank you!

Show all work and calculations:
1. The following data were obtained in the determination of the density of water:
Density (g/mL): 0.986, 0.984, 0,954, 0.990, 0.980
a.
Determine the mean and standard deviation for this data set.
Ncan: 0.979
Stenderd Devietion- 0.0128
b. Perform a Grubbs' outlier test. Can a data point be discarded at the 90% confidence level?
We con
discord the 0.954.
c. Determine the mean, standard deviation, and confidence interval (at the 90% level) of the
remaining data points.
Mean= 0.985
starderd Daviction= 0.003
d. In the Grubbs' test, is there a higher level of confidence that would require you to keep the
outlier (0.954) in the data set? If so, what level is that? Explain why using a higher level of
confidence makes it more difficult to discard an outlier.
Transcribed Image Text:Show all work and calculations: 1. The following data were obtained in the determination of the density of water: Density (g/mL): 0.986, 0.984, 0,954, 0.990, 0.980 a. Determine the mean and standard deviation for this data set. Ncan: 0.979 Stenderd Devietion- 0.0128 b. Perform a Grubbs' outlier test. Can a data point be discarded at the 90% confidence level? We con discord the 0.954. c. Determine the mean, standard deviation, and confidence interval (at the 90% level) of the remaining data points. Mean= 0.985 starderd Daviction= 0.003 d. In the Grubbs' test, is there a higher level of confidence that would require you to keep the outlier (0.954) in the data set? If so, what level is that? Explain why using a higher level of confidence makes it more difficult to discard an outlier.
PENDIX 2: Critical Grubbs Value (gcrit) Table
95% confidence
99% confidence
Number of
90% confidence
Observations (n)
1.155
1.153
1.463
1.148
1.492
4
1.425
1.602
1.672
1.749
1.729
1.822
1.944
6.
1.828
1.938
2.097
7.
1.909
2.032
2.221
1.977
2.110
2.323
9.
10
2.036
2.176
2.410
Transcribed Image Text:PENDIX 2: Critical Grubbs Value (gcrit) Table 95% confidence 99% confidence Number of 90% confidence Observations (n) 1.155 1.153 1.463 1.148 1.492 4 1.425 1.602 1.672 1.749 1.729 1.822 1.944 6. 1.828 1.938 2.097 7. 1.909 2.032 2.221 1.977 2.110 2.323 9. 10 2.036 2.176 2.410
Expert Solution
Step 1

I am only solving C & D that based on your calculations.

c) We see that, removing the outlier value, there are 4 data points.

Hence, sample size = n = 4.

Mean = m = 0.983

S.D. = s = 0.003

We see that, for sample size (no. of observations) 4, the 90% confidence level is 1.425.

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