I am super stuck on this problem!: Solve yy'+ x =(x^2+y^2)^1/2 I know that I'm supposed to use substitution. I used v=y^2 which v'=2yy' and sub it into the equation. After the substitution, I would get v/2 + x = (x^2+v)^(1/2). After sub, I got stuck in how to separate the v and x with the square root going on. Please help me. Thank you.
I am super stuck on this problem!: Solve yy'+ x =(x^2+y^2)^1/2 I know that I'm supposed to use substitution. I used v=y^2 which v'=2yy' and sub it into the equation. After the substitution, I would get v/2 + x = (x^2+v)^(1/2). After sub, I got stuck in how to separate the v and x with the square root going on. Please help me. Thank you.
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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I am super stuck on this problem!:
Solve yy'+ x =(x^2+y^2)^1/2
I know that I'm supposed to use substitution. I used v=y^2 which v'=2yy' and sub it into the equation. After the substitution, I would get v/2 + x = (x^2+v)^(1/2). After sub, I got stuck in how to separate the v and x with the square root going on. Please help me. Thank you.
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