# I am super stuck on this problem!:Solve yy'+ x =(x^2+y^2)^1/2I know that I'm supposed to use substitution. I used v=y^2  which v'=2yy' and sub it into the equation. After the substitution, I would get v/2 + x = (x^2+v)^(1/2). After sub, I got stuck in how to separate the v and x with the square root going on. Please help me. Thank you.

Question
Asked Oct 10, 2019
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I am super stuck on this problem!:

Solve yy'+ x =(x^2+y^2)^1/2

I know that I'm supposed to use substitution. I used v=y^2  which v'=2yy' and sub it into the equation. After the substitution, I would get v/2 + x = (x^2+v)^(1/2). After sub, I got stuck in how to separate the v and x with the square root going on. Please help me. Thank you.

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## Expert Answer

Step 1

We need to solve yy'+ x = (x2+y2)1/2 by the method of substitution.

Let us re-write the given differential equation to visualize the substitution easily.

Step 2

Now,

Step 3

Solving furt...

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