I am trying to figure out these four things.What is the independent variable, what is the dependent variable, what are the controlled variables and why this experiment doesn’t use a control. Vte, green, pink, blackish/purpleAs you know from your experiments with the enzyme amylase, starch reacts with iodine to 1omm ablackish/purple color. In leaves that are actively photosynthesizing, the glucose produced Viaphotosynthesis is immediately converted into starch for storage. If leaves are placed in a near-bolinngalcohol bath, the alcohol will dissolve and extract the pigments, leaving the starch behind. Leaves treatedin this way become a light beige color, and are largely translucent. Because iodine reacts with starch toproduce a dark color, covering the cleared leaf with iodine will show where starch is present, and thereforewhere photosynthesis occurred in the leaf. You can deduce which pigments are photosynthetically activeby comparing the location of starch in the leaf to the location of different pigments.The question you are addressing is: Which pigments are most active in photosynthesis?Alternative Hypotheses: In this experiment, there are several alternative hypotheses. They are asfollows:H1. Chlorophylls are the most photo-synthetically active pigments.H2. Xanthophylls are the most photosynthetically active pigments.H3. Carotenes are the most photo-synthetically active pigments.H4. Anthocyanins are the most photo-synthetically active pigments.

In the experiment, independent variables are not dependent upon other variables and are not altered…

Answered: I am trying to figure out these four…

I am trying to figure out these four things. What is the independent variable, what is the dependent variable, what are the controlled variables and why this experiment doesn’t use a control.

Biochemistry

6th Edition

ISBN:9781305577206

Author:Reginald H. Garrett, Charles M. Grisham

Publisher:Reginald H. Garrett, Charles M. Grisham

Chapter21: Photosynthesis

Section: Chapter Questions

Problem 5P: The Relative Efficiency of ATP Synthesis in Noncyclic versus Cyclic Photophosphorylation If...

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Question

I am trying to figure out these four things. What is the independent variable, what is the dependent variable, what are the controlled variables and why this experiment doesn’t use a control.

Vte, green, pink, blackish/purple
As you know from your experiments with the enzyme amylase, starch reacts with iodine to 1omm a
blackish/purple color. In leaves that are actively photosynthesizing, the glucose produced Via
photosynthesis is immediately converted into starch for storage. If leaves are placed in a near-bolinng
alcohol bath, the alcohol will dissolve and extract the pigments, leaving the starch behind. Leaves treated
in this way become a light beige color, and are largely translucent. Because iodine reacts with starch to
produce a dark color, covering the cleared leaf with iodine will show where starch is present, and therefore
where photosynthesis occurred in the leaf. You can deduce which pigments are photosynthetically active
by comparing the location of starch in the leaf to the location of different pigments.
The question you are addressing is: Which pigments are most active in photosynthesis?
Alternative Hypotheses: In this experiment, there are several alternative hypotheses. They are as
follows:
H1. Chlorophylls are the most photo-synthetically active pigments.
H2. Xanthophylls are the most photosynthetically active pigments.
H3. Carotenes are the most photo-synthetically active pigments.
H4. Anthocyanins are the most photo-synthetically active pigments.

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